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431131212223 = 4310026307261
BaseRepresentation
bin1100100011000010110…
…11000011100110111111
31112012211021102210210221
412101201123003212333
524030424042242343
6530020422042211
743101555560455
oct6214133034677
91465737383727
10431131212223
11156929369968
126b680b79367
133186a191a8a
1416c1c9529d5
15b3349c15ed
hex64616c39bf

431131212223 has 4 divisors (see below), whose sum is σ = 441157519528. Its totient is φ = 421104904920.

The previous prime is 431131212191. The next prime is 431131212257. The reversal of 431131212223 is 322212131134.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 431131212223 - 25 = 431131212191 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (431131212023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5013153588 + ... + 5013153673.

It is an arithmetic number, because the mean of its divisors is an integer number (110289379882).

Almost surely, 2431131212223 is an apocalyptic number.

431131212223 is a gapful number since it is divisible by the number (43) formed by its first and last digit.

431131212223 is a deficient number, since it is larger than the sum of its proper divisors (10026307305).

431131212223 is a wasteful number, since it uses less digits than its factorization.

431131212223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10026307304.

The product of its digits is 1728, while the sum is 25.

Adding to 431131212223 its reverse (322212131134), we get a palindrome (753343343357).

The spelling of 431131212223 in words is "four hundred thirty-one billion, one hundred thirty-one million, two hundred twelve thousand, two hundred twenty-three".

Divisors: 1 43 10026307261 431131212223