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431132433334051 is a prime number
BaseRepresentation
bin110001000000111001101011…
…1100010100011111100100011
32002112111212011120001201112011
41202001303113202203330203
5423002133210413142201
64124535301114413351
7156545201416004401
oct14201632742437443
92075455146051464
10431132433334051
11115410269021649
124043042b731257
13156747c9cb7697
147866cc7762471
1534c9b25e40151
hex1881cd78a3f23

431132433334051 has 2 divisors, whose sum is σ = 431132433334052. Its totient is φ = 431132433334050.

The previous prime is 431132433334019. The next prime is 431132433334073. The reversal of 431132433334051 is 150433334231134.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 431132433334051 - 25 = 431132433334019 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 431132433333995 and 431132433334013.

It is not a weakly prime, because it can be changed into another prime (431132433334651) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215566216667025 + 215566216667026.

It is an arithmetic number, because the mean of its divisors is an integer number (215566216667026).

Almost surely, 2431132433334051 is an apocalyptic number.

431132433334051 is a deficient number, since it is larger than the sum of its proper divisors (1).

431132433334051 is an equidigital number, since it uses as much as digits as its factorization.

431132433334051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 466560, while the sum is 40.

Adding to 431132433334051 its reverse (150433334231134), we get a palindrome (581565767565185).

The spelling of 431132433334051 in words is "four hundred thirty-one trillion, one hundred thirty-two billion, four hundred thirty-three million, three hundred thirty-four thousand, fifty-one".