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43114150343 = 1128313849711
BaseRepresentation
bin101000001001110011…
…011011100111000111
311010021200212202200002
4220021303123213013
51201244210302333
631450101511515
73054260142215
oct501163334707
9133250782602
1043114150343
11173148a5310
128432a1259b
1340b12c3284
142130009cb5
1511c50c80e8
hexa09cdb9c7

43114150343 has 8 divisors (see below), whose sum is σ = 47199818496. Its totient is φ = 39056182200.

The previous prime is 43114150319. The next prime is 43114150357. The reversal of 43114150343 is 34305141134.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 43114150343 - 218 = 43113888199 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43114150393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6921743 + ... + 6927968.

It is an arithmetic number, because the mean of its divisors is an integer number (5899977312).

Almost surely, 243114150343 is an apocalyptic number.

43114150343 is a deficient number, since it is larger than the sum of its proper divisors (4085668153).

43114150343 is a wasteful number, since it uses less digits than its factorization.

43114150343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13850005.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 43114150343 its reverse (34305141134), we get a palindrome (77419291477).

The spelling of 43114150343 in words is "forty-three billion, one hundred fourteen million, one hundred fifty thousand, three hundred forty-three".

Divisors: 1 11 283 3113 13849711 152346821 3919468213 43114150343