Base | Representation |
---|---|
bin | 110001000001000111000010… |
… | …1110001010010000001000111 |
3 | 2002112121121020012210222011012 |
4 | 1202002032011301102001013 |
5 | 423003120441303412020 |
6 | 4125000404215032435 |
7 | 156550235434423445 |
oct | 14202160561220107 |
9 | 2075547205728135 |
10 | 431161126232135 |
11 | 115421452457662 |
12 | 40435ab896b71b |
13 | 156774206290a0 |
14 | 786844a35bb95 |
15 | 34ca754e247c5 |
hex | 1882385c52047 |
431161126232135 has 32 divisors (see below), whose sum is σ = 562301162559360. Its totient is φ = 315478645751808.
The previous prime is 431161126232119. The next prime is 431161126232167. The reversal of 431161126232135 is 531232621161134.
It is a cyclic number.
It is not a de Polignac number, because 431161126232135 - 24 = 431161126232119 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 431161126232092 and 431161126232101.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 14014502 + ... + 32538108.
It is an arithmetic number, because the mean of its divisors is an integer number (17571911329980).
Almost surely, 2431161126232135 is an apocalyptic number.
431161126232135 is a deficient number, since it is larger than the sum of its proper divisors (131140036327225).
431161126232135 is a wasteful number, since it uses less digits than its factorization.
431161126232135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18526907.
The product of its digits is 155520, while the sum is 41.
Adding to 431161126232135 its reverse (531232621161134), we get a palindrome (962393747393269).
The spelling of 431161126232135 in words is "four hundred thirty-one trillion, one hundred sixty-one billion, one hundred twenty-six million, two hundred thirty-two thousand, one hundred thirty-five".
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