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431163312031339 is a prime number
BaseRepresentation
bin110001000001001000000100…
…0000011011100011001101011
32002112121210212112210001222021
41202002100020003130121223
5423003134430340000324
64125001405140205311
7156550343545416046
oct14202201003343153
92075553775701867
10431163312031339
11115422374267988
1240436408999837
13156776ab427ab4
1478685b677dc5d
1534ca831c88ae4
hex18824080dc66b

431163312031339 has 2 divisors, whose sum is σ = 431163312031340. Its totient is φ = 431163312031338.

The previous prime is 431163312031303. The next prime is 431163312031349. The reversal of 431163312031339 is 933130213361134.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 431163312031339 - 215 = 431163311998571 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 431163312031295 and 431163312031304.

It is not a weakly prime, because it can be changed into another prime (431163312031349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215581656015669 + 215581656015670.

It is an arithmetic number, because the mean of its divisors is an integer number (215581656015670).

Almost surely, 2431163312031339 is an apocalyptic number.

431163312031339 is a deficient number, since it is larger than the sum of its proper divisors (1).

431163312031339 is an equidigital number, since it uses as much as digits as its factorization.

431163312031339 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 314928, while the sum is 43.

The spelling of 431163312031339 in words is "four hundred thirty-one trillion, one hundred sixty-three billion, three hundred twelve million, thirty-one thousand, three hundred thirty-nine".