Base | Representation |
---|---|
bin | 110001000001011011001010… |
… | …1001011111001010101100011 |
3 | 2002112202201202110212102211202 |
4 | 1202002312111023321111203 |
5 | 423004322434120241011 |
6 | 4125032311523031415 |
7 | 156553325250116045 |
oct | 14202662513712543 |
9 | 2075681673772752 |
10 | 431204334540131 |
11 | 115438805412a09 |
12 | 4044235720b56b |
13 | 1567b518298839 |
14 | 786a588a77a95 |
15 | 34cb9333eb23b |
hex | 1882d952f9563 |
431204334540131 has 16 divisors (see below), whose sum is σ = 437197478868864. Its totient is φ = 425242834308864.
The previous prime is 431204334540079. The next prime is 431204334540179. The reversal of 431204334540131 is 131045433402134.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-431204334540131 is a prime.
It is a super-2 number, since 2×4312043345401312 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (431204334540631) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1858948100 + ... + 1859180046.
It is an arithmetic number, because the mean of its divisors is an integer number (27324842429304).
Almost surely, 2431204334540131 is an apocalyptic number.
431204334540131 is a deficient number, since it is larger than the sum of its proper divisors (5993144328733).
431204334540131 is a wasteful number, since it uses less digits than its factorization.
431204334540131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 300050.
The product of its (nonzero) digits is 207360, while the sum is 38.
Adding to 431204334540131 its reverse (131045433402134), we get a palindrome (562249767942265).
The spelling of 431204334540131 in words is "four hundred thirty-one trillion, two hundred four billion, three hundred thirty-four million, five hundred forty thousand, one hundred thirty-one".
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