Base | Representation |
---|---|
bin | 10011100110111110000100… |
… | …01010111110101000101011 |
3 | 12122200021101012122210002012 |
4 | 21303133002022332220223 |
5 | 21122441122142424233 |
6 | 231413130513430135 |
7 | 12040230363240533 |
oct | 1163370212765053 |
9 | 178607335583065 |
10 | 43120434342443 |
11 | 12815301047867 |
12 | 4a0504226b34b |
13 | 1b0a316288993 |
14 | a9107c29c4c3 |
15 | 4eb9dc610548 |
hex | 2737c22bea2b |
43120434342443 has 2 divisors, whose sum is σ = 43120434342444. Its totient is φ = 43120434342442.
The previous prime is 43120434342313. The next prime is 43120434342487. The reversal of 43120434342443 is 34424343402134.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 43120434342443 - 212 = 43120434338347 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 43120434342443.
It is not a weakly prime, because it can be changed into another prime (43120434342493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21560217171221 + 21560217171222.
It is an arithmetic number, because the mean of its divisors is an integer number (21560217171222).
Almost surely, 243120434342443 is an apocalyptic number.
43120434342443 is a deficient number, since it is larger than the sum of its proper divisors (1).
43120434342443 is an equidigital number, since it uses as much as digits as its factorization.
43120434342443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1327104, while the sum is 41.
Adding to 43120434342443 its reverse (34424343402134), we get a palindrome (77544777744577).
The spelling of 43120434342443 in words is "forty-three trillion, one hundred twenty billion, four hundred thirty-four million, three hundred forty-two thousand, four hundred forty-three".
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