43121001331 has 2 divisors, whose sum is σ = 43121001332. Its totient is φ = 43121001330.

The previous prime is 43121001281. The next prime is 43121001367. The reversal of 43121001331 is 13310012134.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 43121001331 - 2¹¹ = 43120999283 is a prime.

It is a super-2 number, since 2×43121001331² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 43121001299 and 43121001308.

It is not a weakly prime, because it can be changed into another prime (43121001631) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21560500665 + 21560500666.

It is an arithmetic number, because the mean of its divisors is an integer number (21560500666).

Almost surely, 2^43121001331 is an apocalyptic number.

43121001331 is a deficient number, since it is larger than the sum of its proper divisors (1).

43121001331 is an equidigital number, since it uses as much as digits as its factorization.

43121001331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 43121001331 its reverse (13310012134), we get a palindrome (56431013465).

The spelling of 43121001331 in words is "forty-three billion, one hundred twenty-one million, one thousand, three hundred thirty-one".