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4312130530313 is a prime number
BaseRepresentation
bin111110101111111111000…
…000100010110000001001
3120021020100210100111221202
4332233333000202300021
51031122220403432223
613100544310313545
7623353420512164
oct76577700426011
916236323314852
104312130530313
1114128452a3931
125978779588b5
1325382ab31b18
1410c9cb55aadb
157727d5c0428
hex3ebff022c09

4312130530313 has 2 divisors, whose sum is σ = 4312130530314. Its totient is φ = 4312130530312.

The previous prime is 4312130530297. The next prime is 4312130530321. The reversal of 4312130530313 is 3130350312134.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2574381742144 + 1737748788169 = 1604488^2 + 1318237^2 .

It is a cyclic number.

It is not a de Polignac number, because 4312130530313 - 24 = 4312130530297 is a prime.

It is a super-2 number, since 2×43121305303132 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4312130530333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2156065265156 + 2156065265157.

It is an arithmetic number, because the mean of its divisors is an integer number (2156065265157).

Almost surely, 24312130530313 is an apocalyptic number.

It is an amenable number.

4312130530313 is a deficient number, since it is larger than the sum of its proper divisors (1).

4312130530313 is an equidigital number, since it uses as much as digits as its factorization.

4312130530313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9720, while the sum is 29.

Adding to 4312130530313 its reverse (3130350312134), we get a palindrome (7442480842447).

The spelling of 4312130530313 in words is "four trillion, three hundred twelve billion, one hundred thirty million, five hundred thirty thousand, three hundred thirteen".