Base | Representation |
---|---|
bin | 110001000001101100000101… |
… | …1110001111111001101100011 |
3 | 2002112220012120201202002010122 |
4 | 1202003120023301333031203 |
5 | 423010421410044204043 |
6 | 4125101122453350455 |
7 | 156556053106166252 |
oct | 14203301361771543 |
9 | 2075805521662118 |
10 | 431240683975523 |
11 | 115452168756804 |
12 | 4044940063842b |
13 | 15681a8bc458a6 |
14 | 786c236492799 |
15 | 34cc85e684368 |
hex | 188360bc7f363 |
431240683975523 has 2 divisors, whose sum is σ = 431240683975524. Its totient is φ = 431240683975522.
The previous prime is 431240683975441. The next prime is 431240683975537. The reversal of 431240683975523 is 325579386042134.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 431240683975523 - 28 = 431240683975267 is a prime.
It is not a weakly prime, because it can be changed into another prime (431240683975583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215620341987761 + 215620341987762.
It is an arithmetic number, because the mean of its divisors is an integer number (215620341987762).
It is a 2-persistent number, because it is pandigital, and so is 2⋅431240683975523 = 862481367951046, but 3⋅431240683975523 = 1293722051926569 is not.
Almost surely, 2431240683975523 is an apocalyptic number.
431240683975523 is a deficient number, since it is larger than the sum of its proper divisors (1).
431240683975523 is an equidigital number, since it uses as much as digits as its factorization.
431240683975523 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 130636800, while the sum is 62.
The spelling of 431240683975523 in words is "four hundred thirty-one trillion, two hundred forty billion, six hundred eighty-three million, nine hundred seventy-five thousand, five hundred twenty-three".
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