Base | Representation |
---|---|
bin | 101000001010011110… |
… | …011011110011101111 |
3 | 11010022111002111022121 |
4 | 220022132123303233 |
5 | 1201310102021333 |
6 | 31451143253411 |
7 | 3054455023132 |
oct | 501236336357 |
9 | 133274074277 |
10 | 43125423343 |
11 | 173201a4942 |
12 | 843674a267 |
13 | 40b373c3a2 |
14 | 2131702219 |
15 | 11c60a332d |
hex | a0a79bcef |
43125423343 has 4 divisors (see below), whose sum is σ = 43135548568. Its totient is φ = 43115298120.
The previous prime is 43125423311. The next prime is 43125423347. The reversal of 43125423343 is 34332452134.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 43125423343 - 25 = 43125423311 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 43125423299 and 43125423308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (43125423347) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5056221 + ... + 5064742.
It is an arithmetic number, because the mean of its divisors is an integer number (10783887142).
Almost surely, 243125423343 is an apocalyptic number.
43125423343 is a deficient number, since it is larger than the sum of its proper divisors (10125225).
43125423343 is a wasteful number, since it uses less digits than its factorization.
43125423343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10125224.
The product of its digits is 103680, while the sum is 34.
Adding to 43125423343 its reverse (34332452134), we get a palindrome (77457875477).
The spelling of 43125423343 in words is "forty-three billion, one hundred twenty-five million, four hundred twenty-three thousand, three hundred forty-three".
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