Base | Representation |
---|---|
bin | 111110110000011101101… |
… | …100111000111011111001 |
3 | 120021021200200022021010211 |
4 | 332300131230320323321 |
5 | 1031124244220100433 |
6 | 13101111343311121 |
7 | 623402242446655 |
oct | 76603554707371 |
9 | 16237620267124 |
10 | 4312645471993 |
11 | 1412a89a36171 |
12 | 5979a02ab4a1 |
13 | 2538b0718b41 |
14 | 10ca39ac1a65 |
15 | 772ad8da8cd |
hex | 3ec1db38ef9 |
4312645471993 has 2 divisors, whose sum is σ = 4312645471994. Its totient is φ = 4312645471992.
The previous prime is 4312645471891. The next prime is 4312645472119. The reversal of 4312645471993 is 3991745462134.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3206294915769 + 1106350556224 = 1790613^2 + 1051832^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4312645471993 is a prime.
It is not a weakly prime, because it can be changed into another prime (4312645471093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2156322735996 + 2156322735997.
It is an arithmetic number, because the mean of its divisors is an integer number (2156322735997).
Almost surely, 24312645471993 is an apocalyptic number.
It is an amenable number.
4312645471993 is a deficient number, since it is larger than the sum of its proper divisors (1).
4312645471993 is an equidigital number, since it uses as much as digits as its factorization.
4312645471993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 19595520, while the sum is 58.
The spelling of 4312645471993 in words is "four trillion, three hundred twelve billion, six hundred forty-five million, four hundred seventy-one thousand, nine hundred ninety-three".
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