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43130041223411 is a prime number
BaseRepresentation
bin10011100111001111111101…
…10010010100100011110011
312122201012011201200220021102
421303213332302110203303
521123120311023122121
6231421400054315015
712041020425340052
oct1163477662244363
9178635151626242
1043130041223411
111281939096670a
124a06a83658a6b
131b0b1b76a382c
14a9171012c399
154ebda0c1890b
hex2739fec948f3

43130041223411 has 2 divisors, whose sum is σ = 43130041223412. Its totient is φ = 43130041223410.

The previous prime is 43130041223393. The next prime is 43130041223491. The reversal of 43130041223411 is 11432214003134.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-43130041223411 is a prime.

It is a super-2 number, since 2×431300412234112 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (43130041223491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21565020611705 + 21565020611706.

It is an arithmetic number, because the mean of its divisors is an integer number (21565020611706).

Almost surely, 243130041223411 is an apocalyptic number.

43130041223411 is a deficient number, since it is larger than the sum of its proper divisors (1).

43130041223411 is an equidigital number, since it uses as much as digits as its factorization.

43130041223411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 43130041223411 its reverse (11432214003134), we get a palindrome (54562255226545).

The spelling of 43130041223411 in words is "forty-three trillion, one hundred thirty billion, forty-one million, two hundred twenty-three thousand, four hundred eleven".