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43130443101 = 314376814367
BaseRepresentation
bin101000001010110001…
…100101010101011101
311010022211112112010120
4220022301211111131
51201312343134401
631451443025153
73054545501034
oct501261452535
9133284475116
1043130443101
11173230132a9
12843836b1b9
1340b47a9165
14213224b71b
1511c6745836
hexa0ac6555d

43130443101 has 4 divisors (see below), whose sum is σ = 57507257472. Its totient is φ = 28753628732.

The previous prime is 43130443049. The next prime is 43130443117. The reversal of 43130443101 is 10134403134.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 43130443101 - 231 = 40982959453 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43130443171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7188407181 + ... + 7188407186.

It is an arithmetic number, because the mean of its divisors is an integer number (14376814368).

Almost surely, 243130443101 is an apocalyptic number.

It is an amenable number.

43130443101 is a deficient number, since it is larger than the sum of its proper divisors (14376814371).

43130443101 is a wasteful number, since it uses less digits than its factorization.

43130443101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14376814370.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 43130443101 its reverse (10134403134), we get a palindrome (53264846235).

The spelling of 43130443101 in words is "forty-three billion, one hundred thirty million, four hundred forty-three thousand, one hundred one".

Divisors: 1 3 14376814367 43130443101