Base | Representation |
---|---|
bin | 110001000010001101011001… |
… | …0100110011010011100001101 |
3 | 2002120011001011221220222110211 |
4 | 1202010122302212122130031 |
5 | 423013104342231310013 |
6 | 4125154031301402421 |
7 | 156564164310162523 |
oct | 14204326246323415 |
9 | 2076131157828424 |
10 | 431312202213133 |
11 | 11547a5289551aa |
12 | 4045b23ba09411 |
13 | 15688748a99697 |
14 | 787189c998313 |
15 | 34ce6481e323d |
hex | 18846b299a70d |
431312202213133 has 4 divisors (see below), whose sum is σ = 435758719761820. Its totient is φ = 426865684664448.
The previous prime is 431312202213121. The next prime is 431312202213209. The reversal of 431312202213133 is 331312202213134.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 62021342381769 + 369290859831364 = 7875363^2 + 19216942^2 .
It is a cyclic number.
It is not a de Polignac number, because 431312202213133 - 213 = 431312202204941 is a prime.
It is a super-2 number, since 2×4313122022131332 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 431312202213095 and 431312202213104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (431312202243133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2223258774198 + ... + 2223258774391.
It is an arithmetic number, because the mean of its divisors is an integer number (108939679940455).
Almost surely, 2431312202213133 is an apocalyptic number.
It is an amenable number.
431312202213133 is a deficient number, since it is larger than the sum of its proper divisors (4446517548687).
431312202213133 is an equidigital number, since it uses as much as digits as its factorization.
431312202213133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4446517548686.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 431312202213133 its reverse (331312202213134), we get a palindrome (762624404426267).
Subtracting from 431312202213133 its reverse (331312202213134), we obtain a palindrome (99999999999999).
The spelling of 431312202213133 in words is "four hundred thirty-one trillion, three hundred twelve billion, two hundred two million, two hundred thirteen thousand, one hundred thirty-three".
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