Base | Representation |
---|---|
bin | 110001000010001101110111… |
… | …0111010100010010010010000 |
3 | 2002120011010210111000020020211 |
4 | 1202010123232322202102100 |
5 | 423013113430303333404 |
6 | 4125154315530213504 |
7 | 156564231345230530 |
oct | 14204335672422220 |
9 | 2076133714006224 |
10 | 431313214121104 |
11 | 11547a9a8071687 |
12 | 4045b482884294 |
13 | 1568887a6159b3 |
14 | 78719571254c0 |
15 | 34ce6a6e77b04 |
hex | 18846eeea2490 |
431313214121104 has 80 divisors (see below), whose sum is σ = 997785541066752. Its totient is φ = 176596789336704.
The previous prime is 431313214121057. The next prime is 431313214121117. The reversal of 431313214121104 is 401121412313134.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 99602464 + ... + 103842559.
Almost surely, 2431313214121104 is an apocalyptic number.
It is an amenable number.
431313214121104 is an abundant number, since it is smaller than the sum of its proper divisors (566472326945648).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
431313214121104 is a wasteful number, since it uses less digits than its factorization.
431313214121104 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 203445884 (or 203445878 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 31.
Adding to 431313214121104 its reverse (401121412313134), we get a palindrome (832434626434238).
The spelling of 431313214121104 in words is "four hundred thirty-one trillion, three hundred thirteen billion, two hundred fourteen million, one hundred twenty-one thousand, one hundred four".
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