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4313220223133 = 6734364048531
BaseRepresentation
bin111110110000111111111…
…101011001000010011101
3120021100011201210122111002
4332300333331121002131
51031131433334120013
613101244354240045
7623422421656163
oct76607775310235
916240151718432
104313220223133
111413254409208
12597b20886025
13253972814183
1410ca92175233
15772e40bc358
hex3ec3ff5909d

4313220223133 has 4 divisors (see below), whose sum is σ = 4313284339008. Its totient is φ = 4313156107260.

The previous prime is 4313220223121. The next prime is 4313220223139. The reversal of 4313220223133 is 3313220223134.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4313220223133 - 224 = 4313203445917 is a prime.

It is a super-4 number, since 4×43132202231334 (a number of 52 digits) contains 4444 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4313220223096 and 4313220223105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4313220223139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31956923 + ... + 32091608.

It is an arithmetic number, because the mean of its divisors is an integer number (1078321084752).

Almost surely, 24313220223133 is an apocalyptic number.

It is an amenable number.

4313220223133 is a deficient number, since it is larger than the sum of its proper divisors (64115875).

4313220223133 is an equidigital number, since it uses as much as digits as its factorization.

4313220223133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 64115874.

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 4313220223133 its reverse (3313220223134), we get a palindrome (7626440446267).

Subtracting from 4313220223133 its reverse (3313220223134), we obtain a palindrome (999999999999).

The spelling of 4313220223133 in words is "four trillion, three hundred thirteen billion, two hundred twenty million, two hundred twenty-three thousand, one hundred thirty-three".

Divisors: 1 67343 64048531 4313220223133