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4313400012193 is a prime number
BaseRepresentation
bin111110110001001010101…
…011001110110110100001
3120021100122021002212201011
4332301022223032312201
51031132320400342233
613101314255540521
7623430034105426
oct76611253166641
916240567085634
104313400012193
111413336947408
12597b70b2a741
132539a0b4302c
1410caabdb5d4d
1577304c830cd
hex3ec4aaceda1

4313400012193 has 2 divisors, whose sum is σ = 4313400012194. Its totient is φ = 4313400012192.

The previous prime is 4313400012107. The next prime is 4313400012203. The reversal of 4313400012193 is 3912100043134.

4313400012193 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2728651370769 + 1584748641424 = 1651863^2 + 1258868^2 .

It is a cyclic number.

It is not a de Polignac number, because 4313400012193 - 229 = 4312863141281 is a prime.

It is not a weakly prime, because it can be changed into another prime (4313400072193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2156700006096 + 2156700006097.

It is an arithmetic number, because the mean of its divisors is an integer number (2156700006097).

Almost surely, 24313400012193 is an apocalyptic number.

It is an amenable number.

4313400012193 is a deficient number, since it is larger than the sum of its proper divisors (1).

4313400012193 is an equidigital number, since it uses as much as digits as its factorization.

4313400012193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 31.

The spelling of 4313400012193 in words is "four trillion, three hundred thirteen billion, four hundred million, twelve thousand, one hundred ninety-three".