Base | Representation |
---|---|
bin | 111110110001001010111… |
… | …011001000010011011001 |
3 | 120021100122112221121102021 |
4 | 332301022323020103121 |
5 | 1031132322432222143 |
6 | 13101314525134441 |
7 | 623430114403501 |
oct | 76611273102331 |
9 | 16240575847367 |
10 | 4313404179673 |
11 | 1413339233506 |
12 | 597b723ba421 |
13 | 2539a1971bb4 |
14 | 10caac77ca01 |
15 | 77305307ced |
hex | 3ec4aec84d9 |
4313404179673 has 2 divisors, whose sum is σ = 4313404179674. Its totient is φ = 4313404179672.
The previous prime is 4313404179661. The next prime is 4313404179683. The reversal of 4313404179673 is 3769714043134.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4312234334464 + 1169845209 = 2076592^2 + 34203^2 .
It is a cyclic number.
It is not a de Polignac number, because 4313404179673 - 213 = 4313404171481 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4313404179673.
It is not a weakly prime, because it can be changed into another prime (4313404179683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2156702089836 + 2156702089837.
It is an arithmetic number, because the mean of its divisors is an integer number (2156702089837).
Almost surely, 24313404179673 is an apocalyptic number.
It is an amenable number.
4313404179673 is a deficient number, since it is larger than the sum of its proper divisors (1).
4313404179673 is an equidigital number, since it uses as much as digits as its factorization.
4313404179673 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4572288, while the sum is 52.
The spelling of 4313404179673 in words is "four trillion, three hundred thirteen billion, four hundred four million, one hundred seventy-nine thousand, six hundred seventy-three".
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