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43134212823313 is a prime number
BaseRepresentation
bin10011100111010111101110…
…11011101101100100010001
312122201120221110022010112111
421303223313123231210101
521123202331440321223
6231423330034225321
712041226001344643
oct1163536733554421
9178646843263474
1043134212823313
11128201316a5437
124a07848725241
131b0b700a17841
14a919c8190893
154ec04708830d
hex273af76ed911

43134212823313 has 2 divisors, whose sum is σ = 43134212823314. Its totient is φ = 43134212823312.

The previous prime is 43134212823301. The next prime is 43134212823337. The reversal of 43134212823313 is 31332821243134.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 30575779434369 + 12558433388944 = 5529537^2 + 3543788^2 .

It is a cyclic number.

It is not a de Polignac number, because 43134212823313 - 213 = 43134212815121 is a prime.

It is not a weakly prime, because it can be changed into another prime (43134212823113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21567106411656 + 21567106411657.

It is an arithmetic number, because the mean of its divisors is an integer number (21567106411657).

Almost surely, 243134212823313 is an apocalyptic number.

It is an amenable number.

43134212823313 is a deficient number, since it is larger than the sum of its proper divisors (1).

43134212823313 is an equidigital number, since it uses as much as digits as its factorization.

43134212823313 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 248832, while the sum is 40.

The spelling of 43134212823313 in words is "forty-three trillion, one hundred thirty-four billion, two hundred twelve million, eight hundred twenty-three thousand, three hundred thirteen".