Base | Representation |
---|---|
bin | 10011100111010111101110… |
… | …11011101101100100010001 |
3 | 12122201120221110022010112111 |
4 | 21303223313123231210101 |
5 | 21123202331440321223 |
6 | 231423330034225321 |
7 | 12041226001344643 |
oct | 1163536733554421 |
9 | 178646843263474 |
10 | 43134212823313 |
11 | 128201316a5437 |
12 | 4a07848725241 |
13 | 1b0b700a17841 |
14 | a919c8190893 |
15 | 4ec04708830d |
hex | 273af76ed911 |
43134212823313 has 2 divisors, whose sum is σ = 43134212823314. Its totient is φ = 43134212823312.
The previous prime is 43134212823301. The next prime is 43134212823337. The reversal of 43134212823313 is 31332821243134.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 30575779434369 + 12558433388944 = 5529537^2 + 3543788^2 .
It is a cyclic number.
It is not a de Polignac number, because 43134212823313 - 213 = 43134212815121 is a prime.
It is not a weakly prime, because it can be changed into another prime (43134212823113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21567106411656 + 21567106411657.
It is an arithmetic number, because the mean of its divisors is an integer number (21567106411657).
Almost surely, 243134212823313 is an apocalyptic number.
It is an amenable number.
43134212823313 is a deficient number, since it is larger than the sum of its proper divisors (1).
43134212823313 is an equidigital number, since it uses as much as digits as its factorization.
43134212823313 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 248832, while the sum is 40.
The spelling of 43134212823313 in words is "forty-three trillion, one hundred thirty-four billion, two hundred twelve million, eight hundred twenty-three thousand, three hundred thirteen".
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