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4313424344153 is a prime number
BaseRepresentation
bin111110110001001100001…
…000000011010001011001
3120021100200221220001212212
4332301030020003101121
51031132343113003103
613101320525244505
7623430450656201
oct76611410032131
916240627801785
104313424344153
111413349656371
12597b79103735
132539a5bb2142
1410cab130b401
1577306e8c7d8
hex3ec4c203459

4313424344153 has 2 divisors, whose sum is σ = 4313424344154. Its totient is φ = 4313424344152.

The previous prime is 4313424344101. The next prime is 4313424344167. The reversal of 4313424344153 is 3514434243134.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4118107193344 + 195317150809 = 2029312^2 + 441947^2 .

It is a cyclic number.

It is not a de Polignac number, because 4313424344153 - 28 = 4313424343897 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 4313424344153.

It is not a weakly prime, because it can be changed into another prime (4313424344353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2156712172076 + 2156712172077.

It is an arithmetic number, because the mean of its divisors is an integer number (2156712172077).

Almost surely, 24313424344153 is an apocalyptic number.

It is an amenable number.

4313424344153 is a deficient number, since it is larger than the sum of its proper divisors (1).

4313424344153 is an equidigital number, since it uses as much as digits as its factorization.

4313424344153 is an evil number, because the sum of its binary digits is even.

The product of its digits is 829440, while the sum is 41.

Adding to 4313424344153 its reverse (3514434243134), we get a palindrome (7827858587287).

The spelling of 4313424344153 in words is "four trillion, three hundred thirteen billion, four hundred twenty-four million, three hundred forty-four thousand, one hundred fifty-three".