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43141041231 = 334871412387
BaseRepresentation
bin101000001011011010…
…000000110001001111
311010100120110222000220
4220023122000301033
51201323101304411
631452502122423
73055034541261
oct501332006117
9133316428026
1043141041231
1117328aa1892
12843ba20413
1340b6a4a042
142133809b31
1511c763ab06
hexa0b680c4f

43141041231 has 8 divisors (see below), whose sum is σ = 57523177344. Its totient is φ = 28759799640.

The previous prime is 43141041211. The next prime is 43141041239. The reversal of 43141041231 is 13214014134.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 43141041231 - 25 = 43141041199 is a prime.

It is a super-2 number, since 2×431410412312 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43141041239) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 101581 + ... + 310806.

It is an arithmetic number, because the mean of its divisors is an integer number (7190397168).

Almost surely, 243141041231 is an apocalyptic number.

43141041231 is a deficient number, since it is larger than the sum of its proper divisors (14382136113).

43141041231 is a wasteful number, since it uses less digits than its factorization.

43141041231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 447261.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 43141041231 its reverse (13214014134), we get a palindrome (56355055365).

The spelling of 43141041231 in words is "forty-three billion, one hundred forty-one million, forty-one thousand, two hundred thirty-one".

Divisors: 1 3 34871 104613 412387 1237161 14380347077 43141041231