Base | Representation |
---|---|
bin | 1100100011100101101… |
… | …00100111001010100011 |
3 | 1112020120121201110200002 |
4 | 12101302310213022203 |
5 | 24032023304433011 |
6 | 530105410450215 |
7 | 43112032022546 |
oct | 6216264471243 |
9 | 1466517643602 |
10 | 431423124131 |
11 | 156a6911967a |
12 | 6b74289396b |
13 | 318b57ba30c |
14 | 16c4961c85d |
15 | b350433c3b |
hex | 6472d272a3 |
431423124131 has 2 divisors, whose sum is σ = 431423124132. Its totient is φ = 431423124130.
The previous prime is 431423124049. The next prime is 431423124193. The reversal of 431423124131 is 131421324134.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 431423124131 - 222 = 431418929827 is a prime.
It is a super-2 number, since 2×4314231241312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 431423124094 and 431423124103.
It is not a weakly prime, because it can be changed into another prime (431423124031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215711562065 + 215711562066.
It is an arithmetic number, because the mean of its divisors is an integer number (215711562066).
Almost surely, 2431423124131 is an apocalyptic number.
431423124131 is a deficient number, since it is larger than the sum of its proper divisors (1).
431423124131 is an equidigital number, since it uses as much as digits as its factorization.
431423124131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6912, while the sum is 29.
Adding to 431423124131 its reverse (131421324134), we get a palindrome (562844448265).
The spelling of 431423124131 in words is "four hundred thirty-one billion, four hundred twenty-three million, one hundred twenty-four thousand, one hundred thirty-one".
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