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43142414113 is a prime number
BaseRepresentation
bin101000001011011111…
…001111111100100001
311010100200001201021101
4220023133033330201
51201323424222423
631452551354401
73055052316661
oct501337177441
9133320051241
1043142414113
111732984a2a7
128440382a01
1340b710abb6
142133a861a1
1511c780c7ad
hexa0b7cff21

43142414113 has 2 divisors, whose sum is σ = 43142414114. Its totient is φ = 43142414112.

The previous prime is 43142414039. The next prime is 43142414131. The reversal of 43142414113 is 31141424134.

Together with next prime (43142414131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 33136013089 + 10006401024 = 182033^2 + 100032^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-43142414113 is a prime.

It is a super-2 number, since 2×431424141132 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (43142474113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21571207056 + 21571207057.

It is an arithmetic number, because the mean of its divisors is an integer number (21571207057).

Almost surely, 243142414113 is an apocalyptic number.

It is an amenable number.

43142414113 is a deficient number, since it is larger than the sum of its proper divisors (1).

43142414113 is an equidigital number, since it uses as much as digits as its factorization.

43142414113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4608, while the sum is 28.

Adding to 43142414113 its reverse (31141424134), we get a palindrome (74283838247).

The spelling of 43142414113 in words is "forty-three billion, one hundred forty-two million, four hundred fourteen thousand, one hundred thirteen".