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43143444451 is a prime number
BaseRepresentation
bin101000001011100011…
…001011011111100011
311010100202000001122001
4220023203023133203
51201324210210301
631453025424431
73055064140612
oct501343133743
9133322001561
1043143444451
111732a393418
12844079b117
1340b73abb73
142133c73879
1511c7962c01
hexa0b8cb7e3

43143444451 has 2 divisors, whose sum is σ = 43143444452. Its totient is φ = 43143444450.

The previous prime is 43143444401. The next prime is 43143444481. The reversal of 43143444451 is 15444434134.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 43143444451 - 215 = 43143411683 is a prime.

It is a super-2 number, since 2×431434444512 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 43143444451.

It is not a weakly prime, because it can be changed into another prime (43143444401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21571722225 + 21571722226.

It is an arithmetic number, because the mean of its divisors is an integer number (21571722226).

Almost surely, 243143444451 is an apocalyptic number.

43143444451 is a deficient number, since it is larger than the sum of its proper divisors (1).

43143444451 is an equidigital number, since it uses as much as digits as its factorization.

43143444451 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 184320, while the sum is 37.

Adding to 43143444451 its reverse (15444434134), we get a palindrome (58587878585).

The spelling of 43143444451 in words is "forty-three billion, one hundred forty-three million, four hundred forty-four thousand, four hundred fifty-one".