Base | Representation |
---|---|
bin | 10011100111110101111110… |
… | …11100101011010100001011 |
3 | 12122210010212021211222202111 |
4 | 21303322333130223110023 |
5 | 21123434112033440243 |
6 | 231435013350443151 |
7 | 12042342314221123 |
oct | 1163727734532413 |
9 | 178703767758674 |
10 | 43150453421323 |
11 | 12827006032066 |
12 | 4a0aa1b6634b7 |
13 | 1b100bb5a0b51 |
14 | a926c9071c83 |
15 | 4ec697c5739d |
hex | 273ebf72b50b |
43150453421323 has 2 divisors, whose sum is σ = 43150453421324. Its totient is φ = 43150453421322.
The previous prime is 43150453421311. The next prime is 43150453421353. The reversal of 43150453421323 is 32312435405134.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 43150453421323 - 221 = 43150451324171 is a prime.
It is not a weakly prime, because it can be changed into another prime (43150453421353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21575226710661 + 21575226710662.
It is an arithmetic number, because the mean of its divisors is an integer number (21575226710662).
Almost surely, 243150453421323 is an apocalyptic number.
43150453421323 is a deficient number, since it is larger than the sum of its proper divisors (1).
43150453421323 is an equidigital number, since it uses as much as digits as its factorization.
43150453421323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 518400, while the sum is 40.
Adding to 43150453421323 its reverse (32312435405134), we get a palindrome (75462888826457).
The spelling of 43150453421323 in words is "forty-three trillion, one hundred fifty billion, four hundred fifty-three million, four hundred twenty-one thousand, three hundred twenty-three".
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