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4315553550409 is a prime number
BaseRepresentation
bin111110110011001011000…
…010010101000001001001
3120021120012100100221202211
4332303023002111001021
51031201223202103114
613102312105425121
7623534303634463
oct76631302250111
916246170327684
104315553550409
111414241522562
1259847219b1a1
13253c550578ba
1410cc33ddb133
15773cdd736c4
hex3eccb095049

4315553550409 has 2 divisors, whose sum is σ = 4315553550410. Its totient is φ = 4315553550408.

The previous prime is 4315553550361. The next prime is 4315553550421. The reversal of 4315553550409 is 9040553555134.

4315553550409 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4311968534784 + 3585015625 = 2076528^2 + 59875^2 .

It is a cyclic number.

It is not a de Polignac number, because 4315553550409 - 229 = 4315016679497 is a prime.

It is not a weakly prime, because it can be changed into another prime (4315553550479) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2157776775204 + 2157776775205.

It is an arithmetic number, because the mean of its divisors is an integer number (2157776775205).

Almost surely, 24315553550409 is an apocalyptic number.

It is an amenable number.

4315553550409 is a deficient number, since it is larger than the sum of its proper divisors (1).

4315553550409 is an equidigital number, since it uses as much as digits as its factorization.

4315553550409 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4050000, while the sum is 49.

The spelling of 4315553550409 in words is "four trillion, three hundred fifteen billion, five hundred fifty-three million, five hundred fifty thousand, four hundred nine".