Base | Representation |
---|---|
bin | 101000001100100110… |
… | …001111010000111111 |
3 | 11010101222002011121211 |
4 | 220030212033100333 |
5 | 1201343210223201 |
6 | 31454454305251 |
7 | 3055366434622 |
oct | 501446172077 |
9 | 133358064554 |
10 | 43161023551 |
11 | 173392aa8a8 |
12 | 8446658227 |
13 | 40bac253b9 |
14 | 213632bdb9 |
15 | 11c9286651 |
hex | a0c98f43f |
43161023551 has 4 divisors (see below), whose sum is σ = 43450695000. Its totient is φ = 42871352104.
The previous prime is 43161023509. The next prime is 43161023603. The reversal of 43161023551 is 15532016134.
43161023551 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 43161023551 - 211 = 43161021503 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (43161023501) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 144835501 + ... + 144835798.
It is an arithmetic number, because the mean of its divisors is an integer number (10862673750).
Almost surely, 243161023551 is an apocalyptic number.
43161023551 is a deficient number, since it is larger than the sum of its proper divisors (289671449).
43161023551 is a wasteful number, since it uses less digits than its factorization.
43161023551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 289671448.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 43161023551 its reverse (15532016134), we get a palindrome (58693039685).
The spelling of 43161023551 in words is "forty-three billion, one hundred sixty-one million, twenty-three thousand, five hundred fifty-one".
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