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15532016134 = 215151430517
BaseRepresentation
bin11100111011100011…
…11100001000000110
31111002110020011121211
432131301330020012
5223302144004014
611045121002034
71056616646605
oct163561741006
944073204554
1015532016134
116650466678
12301578331a
131606b309bb
14a74b51a3c
1560d8a3cc4
hex39dc7c206

15532016134 has 8 divisors (see below), whose sum is σ = 23452316208. Its totient is φ = 7714577400.

The previous prime is 15532016099. The next prime is 15532016189. The reversal of 15532016134 is 43161023551.

15532016134 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 15532016096 and 15532016105.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25714957 + ... + 25715560.

It is an arithmetic number, because the mean of its divisors is an integer number (2931539526).

Almost surely, 215532016134 is an apocalyptic number.

15532016134 is a deficient number, since it is larger than the sum of its proper divisors (7920300074).

15532016134 is a wasteful number, since it uses less digits than its factorization.

15532016134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51430670.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 15532016134 its reverse (43161023551), we get a palindrome (58693039685).

The spelling of 15532016134 in words is "fifteen billion, five hundred thirty-two million, sixteen thousand, one hundred thirty-four".

Divisors: 1 2 151 302 51430517 102861034 7766008067 15532016134