Base | Representation |
---|---|
bin | 101000001100110101… |
… | …100111110010000111 |
3 | 11010102020200001021210 |
4 | 220030311213302013 |
5 | 1201400223244020 |
6 | 31455120542503 |
7 | 3055445631465 |
oct | 501465476207 |
9 | 133366601253 |
10 | 43165056135 |
11 | 17340604613 |
12 | 8447a81a33 |
13 | 40bba07a46 |
14 | 2136a9b835 |
15 | 11c97d13e0 |
hex | a0cd67c87 |
43165056135 has 32 divisors (see below), whose sum is σ = 69852119040. Its totient is φ = 22760179328.
The previous prime is 43165056107. The next prime is 43165056157. The reversal of 43165056135 is 53165056134.
43165056135 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 43165056135 - 26 = 43165056071 is a prime.
It is a super-2 number, since 2×431650561352 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 43165056093 and 43165056102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 418042 + ... + 510968.
It is an arithmetic number, because the mean of its divisors is an integer number (2182878720).
Almost surely, 243165056135 is an apocalyptic number.
43165056135 is a deficient number, since it is larger than the sum of its proper divisors (26687062905).
43165056135 is a wasteful number, since it uses less digits than its factorization.
43165056135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 93287.
The product of its (nonzero) digits is 162000, while the sum is 39.
Subtracting 43165056135 from its reverse (53165056134), we obtain a palindrome (9999999999).
The spelling of 43165056135 in words is "forty-three billion, one hundred sixty-five million, fifty-six thousand, one hundred thirty-five".
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