Base | Representation |
---|---|
bin | 10011101001010110000111… |
… | …00000000101001011110011 |
3 | 12122222002001220200011002022 |
4 | 21310223003200011023303 |
5 | 21130310310110431011 |
6 | 231514430340542055 |
7 | 12046150226524043 |
oct | 1164530340051363 |
9 | 178862056604068 |
10 | 43202061030131 |
11 | 128469891a3433 |
12 | 4a18a229b192b |
13 | 1b14c2440b993 |
14 | a94dc30b7723 |
15 | 4edbb88008db |
hex | 274ac38052f3 |
43202061030131 has 2 divisors, whose sum is σ = 43202061030132. Its totient is φ = 43202061030130.
The previous prime is 43202061030097. The next prime is 43202061030137. The reversal of 43202061030131 is 13103016020234.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 43202061030131 - 226 = 43201993921267 is a prime.
It is a super-2 number, since 2×432020610301312 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 43202061030131.
It is not a weakly prime, because it can be changed into another prime (43202061030137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21601030515065 + 21601030515066.
It is an arithmetic number, because the mean of its divisors is an integer number (21601030515066).
Almost surely, 243202061030131 is an apocalyptic number.
43202061030131 is a deficient number, since it is larger than the sum of its proper divisors (1).
43202061030131 is an equidigital number, since it uses as much as digits as its factorization.
43202061030131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 26.
Adding to 43202061030131 its reverse (13103016020234), we get a palindrome (56305077050365).
The spelling of 43202061030131 in words is "forty-three trillion, two hundred two billion, sixty-one million, thirty thousand, one hundred thirty-one".
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