Base | Representation |
---|---|
bin | 101000001111000111… |
… | …111100000010010001 |
3 | 11010111220211201210120 |
4 | 220033013330002101 |
5 | 1201440033141423 |
6 | 31503011020453 |
7 | 3056422641501 |
oct | 501707740221 |
9 | 133456751716 |
10 | 43203412113 |
11 | 17360221a74 |
12 | 845889a729 |
13 | 40c69471a4 |
14 | 213bc03a01 |
15 | 11ccd5aee3 |
hex | a0f1fc091 |
43203412113 has 4 divisors (see below), whose sum is σ = 57604549488. Its totient is φ = 28802274740.
The previous prime is 43203412079. The next prime is 43203412121. The reversal of 43203412113 is 31121430234.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 43203412113 - 229 = 42666541201 is a prime.
It is not an unprimeable number, because it can be changed into a prime (43203412183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7200568683 + ... + 7200568688.
It is an arithmetic number, because the mean of its divisors is an integer number (14401137372).
Almost surely, 243203412113 is an apocalyptic number.
It is an amenable number.
43203412113 is a deficient number, since it is larger than the sum of its proper divisors (14401137375).
43203412113 is a wasteful number, since it uses less digits than its factorization.
43203412113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14401137374.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 43203412113 its reverse (31121430234), we get a palindrome (74324842347).
The spelling of 43203412113 in words is "forty-three billion, two hundred three million, four hundred twelve thousand, one hundred thirteen".
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