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432330000001241 is a prime number
BaseRepresentation
bin110001001001100111010110…
…0000100110110100011011001
32002200202100022001000201102012
41202103032230010312203121
5423131243320000014431
64131253354332315305
7160030545266504606
oct14223165404664331
92080670261021365
10432330000001241
1111583213a1a9791
12405a454a312b35
131573070c415794
1478a8c52a316ad
1534ead671bd22b
hex18933ac1368d9

432330000001241 has 2 divisors, whose sum is σ = 432330000001242. Its totient is φ = 432330000001240.

The previous prime is 432330000001231. The next prime is 432330000001313. The reversal of 432330000001241 is 142100000033234.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 410367926851600 + 21962073149641 = 20257540^2 + 4686371^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-432330000001241 is a prime.

It is not a weakly prime, because it can be changed into another prime (432330000001231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 216165000000620 + 216165000000621.

It is an arithmetic number, because the mean of its divisors is an integer number (216165000000621).

Almost surely, 2432330000001241 is an apocalyptic number.

It is an amenable number.

432330000001241 is a deficient number, since it is larger than the sum of its proper divisors (1).

432330000001241 is an equidigital number, since it uses as much as digits as its factorization.

432330000001241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 432330000001241 its reverse (142100000033234), we get a palindrome (574430000034475).

The spelling of 432330000001241 in words is "four hundred thirty-two trillion, three hundred thirty billion, one thousand, two hundred forty-one".