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43234000234 = 221617000117
BaseRepresentation
bin101000010000111100…
…100111110101101010
311010121001101202210221
4220100330213311222
51202020401001414
631510022400254
73060243636625
oct502074476552
9133531352727
1043234000234
1117376514307
128466b9008a
134100096a79
142141cc6dbc
1511d089e224
hexa10f27d6a

43234000234 has 4 divisors (see below), whose sum is σ = 64851000354. Its totient is φ = 21617000116.

The previous prime is 43234000219. The next prime is 43234000237. The reversal of 43234000234 is 43200043234.

43234000234 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 37653462025 + 5580538209 = 194045^2 + 74703^2 .

It is a junction number, because it is equal to n+sod(n) for n = 43234000199 and 43234000208.

It is not an unprimeable number, because it can be changed into a prime (43234000237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10808500057 + ... + 10808500060.

Almost surely, 243234000234 is an apocalyptic number.

43234000234 is a deficient number, since it is larger than the sum of its proper divisors (21617000120).

43234000234 is a wasteful number, since it uses less digits than its factorization.

43234000234 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21617000119.

The product of its (nonzero) digits is 6912, while the sum is 25.

Adding to 43234000234 its reverse (43200043234), we get a palindrome (86434043468).

The spelling of 43234000234 in words is "forty-three billion, two hundred thirty-four million, two hundred thirty-four", and thus it is an aban number.

Divisors: 1 2 21617000117 43234000234