Base | Representation |
---|---|
bin | 10011101010011111000010… |
… | …00110110000010001110010 |
3 | 12200002211010102220110210020 |
4 | 21311033201012300101302 |
5 | 21131431000334204132 |
6 | 231544423322544310 |
7 | 12052034361013410 |
oct | 1165174106602162 |
9 | 180084112813706 |
10 | 43241212413042 |
11 | 1286154a124936 |
12 | 4a2452a668096 |
13 | 1b18823718547 |
14 | a96c58aa22b0 |
15 | 4eec0aa5a52c |
hex | 2753e11b0472 |
43241212413042 has 32 divisors (see below), whose sum is σ = 98838101366784. Its totient is φ = 12354501565200.
The previous prime is 43241212412989. The next prime is 43241212413067. The reversal of 43241212413042 is 24031421214234.
It is a super-3 number, since 3×432412124130423 (a number of 42 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 43241212412994 and 43241212413012.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1382184 + ... + 9401747.
It is an arithmetic number, because the mean of its divisors is an integer number (3088690667712).
Almost surely, 243241212413042 is an apocalyptic number.
43241212413042 is a gapful number since it is divisible by the number (42) formed by its first and last digit.
43241212413042 is an abundant number, since it is smaller than the sum of its proper divisors (55596888953742).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
43241212413042 is a wasteful number, since it uses less digits than its factorization.
43241212413042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10879414.
The product of its (nonzero) digits is 36864, while the sum is 33.
Adding to 43241212413042 its reverse (24031421214234), we get a palindrome (67272633627276).
The spelling of 43241212413042 in words is "forty-three trillion, two hundred forty-one billion, two hundred twelve million, four hundred thirteen thousand, forty-two".
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