Base | Representation |
---|---|
bin | 1100100101011100100… |
… | …00100010110100100001 |
3 | 1112100011010002100200221 |
4 | 12102232100202310201 |
5 | 24041044044131423 |
6 | 530352351443041 |
7 | 43145530631152 |
oct | 6225620426441 |
9 | 1470133070627 |
10 | 432420302113 |
11 | 15742aa95208 |
12 | 6b980826481 |
13 | 31a14279b67 |
14 | 16d01c33929 |
15 | b3acc58e5d |
hex | 64ae422d21 |
432420302113 has 4 divisors (see below), whose sum is σ = 434229592320. Its totient is φ = 430611011908.
The previous prime is 432420302101. The next prime is 432420302131. The reversal of 432420302113 is 311203024234.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311203024234 = 2 ⋅155601512117.
It is a cyclic number.
It is not a de Polignac number, because 432420302113 - 29 = 432420301601 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (432420302513) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 904644745 + ... + 904645222.
It is an arithmetic number, because the mean of its divisors is an integer number (108557398080).
Almost surely, 2432420302113 is an apocalyptic number.
It is an amenable number.
432420302113 is a deficient number, since it is larger than the sum of its proper divisors (1809290207).
432420302113 is a wasteful number, since it uses less digits than its factorization.
432420302113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1809290206.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 432420302113 its reverse (311203024234), we get a palindrome (743623326347).
The spelling of 432420302113 in words is "four hundred thirty-two billion, four hundred twenty million, three hundred two thousand, one hundred thirteen".
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