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4324240120313 is a prime number
BaseRepresentation
bin111110111011010000110…
…010111101100111111001
3120022101121201200102112002
4332323100302331213321
51031322020432322223
613110310053030345
7624262462362251
oct76732062754771
916271551612462
104324240120313
1114179998a7053
1259a0973253b5
13254a0a8b71a9
1410d419944961
157773b78be28
hex3eed0cbd9f9

4324240120313 has 2 divisors, whose sum is σ = 4324240120314. Its totient is φ = 4324240120312.

The previous prime is 4324240120289. The next prime is 4324240120451. The reversal of 4324240120313 is 3130210424234.

4324240120313 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3380052834064 + 944187286249 = 1838492^2 + 971693^2 .

It is a cyclic number.

It is not a de Polignac number, because 4324240120313 - 226 = 4324173011449 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (4324240120913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2162120060156 + 2162120060157.

It is an arithmetic number, because the mean of its divisors is an integer number (2162120060157).

Almost surely, 24324240120313 is an apocalyptic number.

It is an amenable number.

4324240120313 is a deficient number, since it is larger than the sum of its proper divisors (1).

4324240120313 is an equidigital number, since it uses as much as digits as its factorization.

4324240120313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 4324240120313 its reverse (3130210424234), we get a palindrome (7454450544547).

The spelling of 4324240120313 in words is "four trillion, three hundred twenty-four billion, two hundred forty million, one hundred twenty thousand, three hundred thirteen".