Base | Representation |
---|---|
bin | 111111000000111100100… |
… | …100000111001101011011 |
3 | 120022222101001120122110122 |
4 | 333000330210013031123 |
5 | 1031422020320242133 |
6 | 13113155425503455 |
7 | 624566640214223 |
oct | 77007444071533 |
9 | 16288331518418 |
10 | 4330343134043 |
11 | 141a540897653 |
12 | 59b2bb1a1b8b |
13 | 255471110414 |
14 | 10d8382cb083 |
15 | 77997472498 |
hex | 3f03c90735b |
4330343134043 has 2 divisors, whose sum is σ = 4330343134044. Its totient is φ = 4330343134042.
The previous prime is 4330343134037. The next prime is 4330343134063. The reversal of 4330343134043 is 3404313430334.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4330343134043 - 24 = 4330343134027 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4330343133994 and 4330343134012.
It is not a weakly prime, because it can be changed into another prime (4330343134063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2165171567021 + 2165171567022.
It is an arithmetic number, because the mean of its divisors is an integer number (2165171567022).
Almost surely, 24330343134043 is an apocalyptic number.
4330343134043 is a deficient number, since it is larger than the sum of its proper divisors (1).
4330343134043 is an equidigital number, since it uses as much as digits as its factorization.
4330343134043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 186624, while the sum is 35.
Adding to 4330343134043 its reverse (3404313430334), we get a palindrome (7734656564377).
The spelling of 4330343134043 in words is "four trillion, three hundred thirty billion, three hundred forty-three million, one hundred thirty-four thousand, forty-three".
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