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4331012131 is a prime number
BaseRepresentation
bin1000000100010011…
…00000000000100011
3102011211120012201201
410002021200000203
532332214342011
61553432342031
7212216665345
oct40211400043
912154505651
104331012131
11192281a576
12a0a544917
1354038a094
142d12bb295
151a535ccc1
hex102260023

4331012131 has 2 divisors, whose sum is σ = 4331012132. Its totient is φ = 4331012130.

The previous prime is 4331012107. The next prime is 4331012149. The reversal of 4331012131 is 1312101334.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4331012131 - 217 = 4330881059 is a prime.

It is a super-2 number, since 2×43310121312 = 37515332157738322322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4331012099 and 4331012108.

It is not a weakly prime, because it can be changed into another prime (4331012831) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2165506065 + 2165506066.

It is an arithmetic number, because the mean of its divisors is an integer number (2165506066).

Almost surely, 24331012131 is an apocalyptic number.

4331012131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4331012131 is an equidigital number, since it uses as much as digits as its factorization.

4331012131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

The square root of 4331012131 is about 65810.4257014039. The cubic root of 4331012131 is about 1630.0332625227.

Adding to 4331012131 its reverse (1312101334), we get a palindrome (5643113465).

The spelling of 4331012131 in words is "four billion, three hundred thirty-one million, twelve thousand, one hundred thirty-one".