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43311315044 = 2210827828761
BaseRepresentation
bin101000010101100011…
…100011100001100100
311010210102212202210102
4220111203203201210
51202200144040134
631521423443232
73062203050344
oct502543434144
9133712782712
1043311315044
1117406121048
128488a56518
1341130c6b8a
14214c290d24
1511d757237e
hexa158e3864

43311315044 has 6 divisors (see below), whose sum is σ = 75794801334. Its totient is φ = 21655657520.

The previous prime is 43311315037. The next prime is 43311315049. The reversal of 43311315044 is 44051311334.

It is a happy number.

It can be written as a sum of positive squares in only one way, i.e., 32359692544 + 10951622500 = 179888^2 + 104650^2 .

It is a junction number, because it is equal to n+sod(n) for n = 43311314998 and 43311315016.

It is not an unprimeable number, because it can be changed into a prime (43311315049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5413914377 + ... + 5413914384.

It is an arithmetic number, because the mean of its divisors is an integer number (12632466889).

Almost surely, 243311315044 is an apocalyptic number.

It is an amenable number.

43311315044 is a deficient number, since it is larger than the sum of its proper divisors (32483486290).

43311315044 is a wasteful number, since it uses less digits than its factorization.

43311315044 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10827828765 (or 10827828763 counting only the distinct ones).

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 43311315044 its reverse (44051311334), we get a palindrome (87362626378).

The spelling of 43311315044 in words is "forty-three billion, three hundred eleven million, three hundred fifteen thousand, forty-four".

Divisors: 1 2 4 10827828761 21655657522 43311315044