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433114344161 is a prime number
BaseRepresentation
bin1100100110101111010…
…00000110101011100001
31112101221111001100101222
412103113220012223201
524044004233003121
6530545303304425
743201656116312
oct6232750065341
91471844040358
10433114344161
11157756835284
126bb3514b115
1331ac4cb1425
1416d6a09a609
15b3edb510ab
hex64d7a06ae1

433114344161 has 2 divisors, whose sum is σ = 433114344162. Its totient is φ = 433114344160.

The previous prime is 433114344127. The next prime is 433114344241. The reversal of 433114344161 is 161443411334.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 410900230225 + 22214113936 = 641015^2 + 149044^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-433114344161 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (433114344461) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 216557172080 + 216557172081.

It is an arithmetic number, because the mean of its divisors is an integer number (216557172081).

Almost surely, 2433114344161 is an apocalyptic number.

It is an amenable number.

433114344161 is a deficient number, since it is larger than the sum of its proper divisors (1).

433114344161 is an equidigital number, since it uses as much as digits as its factorization.

433114344161 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 41472, while the sum is 35.

Adding to 433114344161 its reverse (161443411334), we get a palindrome (594557755495).

The spelling of 433114344161 in words is "four hundred thirty-three billion, one hundred fourteen million, three hundred forty-four thousand, one hundred sixty-one".