43312023133 has 4 divisors (see below), whose sum is σ = 44046125280. Its totient is φ = 42577920988.

The previous prime is 43312023127. The next prime is 43312023149. The reversal of 43312023133 is 33132021334.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 43312023133 - 2¹⁷ = 43311892061 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 43312023098 and 43312023107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43312023113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 367050985 + ... + 367051102.

It is an arithmetic number, because the mean of its divisors is an integer number (11011531320).

Almost surely, 2^43312023133 is an apocalyptic number.

It is an amenable number.

43312023133 is a deficient number, since it is larger than the sum of its proper divisors (734102147).

43312023133 is an equidigital number, since it uses as much as digits as its factorization.

43312023133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 734102146.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 43312023133 its reverse (33132021334), we get a palindrome (76444044467).

The spelling of 43312023133 in words is "forty-three billion, three hundred twelve million, twenty-three thousand, one hundred thirty-three".