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43312121314055 = 511787493114801
BaseRepresentation
bin10011101100100011000111…
…00110101111101100000111
312200100121011012111212110022
421312101203212233230013
521134111211024022210
6232041151442445355
712060124512513266
oct1166214346575407
9180317135455408
1043312121314055
1112889627378770
124a3621996385b
131b22414254b39
14a9a4642b05dd
155019aad55155
hex2764639afb07

43312121314055 has 8 divisors (see below), whose sum is σ = 56699504265744. Its totient is φ = 31499724592000.

The previous prime is 43312121314037. The next prime is 43312121314057. The reversal of 43312121314055 is 55041312121334.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-43312121314055 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43312121314057) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 393746557346 + ... + 393746557455.

It is an arithmetic number, because the mean of its divisors is an integer number (7087438033218).

Almost surely, 243312121314055 is an apocalyptic number.

43312121314055 is a deficient number, since it is larger than the sum of its proper divisors (13387382951689).

43312121314055 is a wasteful number, since it uses less digits than its factorization.

43312121314055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 787493114817.

The product of its (nonzero) digits is 43200, while the sum is 35.

Adding to 43312121314055 its reverse (55041312121334), we get a palindrome (98353433435389).

The spelling of 43312121314055 in words is "forty-three trillion, three hundred twelve billion, one hundred twenty-one million, three hundred fourteen thousand, fifty-five".

Divisors: 1 5 11 55 787493114801 3937465574005 8662424262811 43312121314055