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43312121314057 is a prime number
BaseRepresentation
bin10011101100100011000111…
…00110101111101100001001
312200100121011012111212110101
421312101203212233230021
521134111211024022212
6232041151442445401
712060124512513301
oct1166214346575411
9180317135455411
1043312121314057
1112889627378772
124a36219963861
131b22414254b3b
14a9a4642b0601
155019aad55157
hex2764639afb09

43312121314057 has 2 divisors, whose sum is σ = 43312121314058. Its totient is φ = 43312121314056.

The previous prime is 43312121314037. The next prime is 43312121314087. The reversal of 43312121314057 is 75041312121334.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 29350270572921 + 13961850741136 = 5417589^2 + 3736556^2 .

It is a cyclic number.

It is not a de Polignac number, because 43312121314057 - 235 = 43277761575689 is a prime.

It is not a weakly prime, because it can be changed into another prime (43312121314027) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21656060657028 + 21656060657029.

It is an arithmetic number, because the mean of its divisors is an integer number (21656060657029).

Almost surely, 243312121314057 is an apocalyptic number.

It is an amenable number.

43312121314057 is a deficient number, since it is larger than the sum of its proper divisors (1).

43312121314057 is an equidigital number, since it uses as much as digits as its factorization.

43312121314057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60480, while the sum is 37.

The spelling of 43312121314057 in words is "forty-three trillion, three hundred twelve billion, one hundred twenty-one million, three hundred fourteen thousand, fifty-seven".