Base | Representation |
---|---|
bin | 101000010101100111… |
… | …000000101101010011 |
3 | 11010210111120210112202 |
4 | 220111213000231103 |
5 | 1202200412033021 |
6 | 31521455113415 |
7 | 3062213542553 |
oct | 502547005523 |
9 | 133714523482 |
10 | 43312221011 |
11 | 1740668a784 |
12 | 848921286b |
13 | 4113353357 |
14 | 214c449163 |
15 | 11d76a0a0b |
hex | a159c0b53 |
43312221011 has 2 divisors, whose sum is σ = 43312221012. Its totient is φ = 43312221010.
The previous prime is 43312220957. The next prime is 43312221023. The reversal of 43312221011 is 11012221334.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 43312221011 - 210 = 43312219987 is a prime.
It is not a weakly prime, because it can be changed into another prime (43312220011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21656110505 + 21656110506.
It is an arithmetic number, because the mean of its divisors is an integer number (21656110506).
Almost surely, 243312221011 is an apocalyptic number.
43312221011 is a deficient number, since it is larger than the sum of its proper divisors (1).
43312221011 is an equidigital number, since it uses as much as digits as its factorization.
43312221011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 43312221011 its reverse (11012221334), we get a palindrome (54324442345).
The spelling of 43312221011 in words is "forty-three billion, three hundred twelve million, two hundred twenty-one thousand, eleven".
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