Base | Representation |
---|---|
bin | 1100100110110000100… |
… | …01000111111111000011 |
3 | 1112101222020021200002111 |
4 | 12103120101013333003 |
5 | 24044020011104121 |
6 | 530550330000151 |
7 | 43202146404016 |
oct | 6233021077703 |
9 | 1471866250074 |
10 | 433125097411 |
11 | 15776190a366 |
12 | 6bb38876057 |
13 | 31ac72a7ab6 |
14 | 16d6b69937d |
15 | b3eea772e1 |
hex | 64d8447fc3 |
433125097411 has 2 divisors, whose sum is σ = 433125097412. Its totient is φ = 433125097410.
The previous prime is 433125097337. The next prime is 433125097469. The reversal of 433125097411 is 114790521334.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 433125097411 - 213 = 433125089219 is a prime.
It is not a weakly prime, because it can be changed into another prime (433125094411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 216562548705 + 216562548706.
It is an arithmetic number, because the mean of its divisors is an integer number (216562548706).
Almost surely, 2433125097411 is an apocalyptic number.
433125097411 is a deficient number, since it is larger than the sum of its proper divisors (1).
433125097411 is an equidigital number, since it uses as much as digits as its factorization.
433125097411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90720, while the sum is 40.
The spelling of 433125097411 in words is "four hundred thirty-three billion, one hundred twenty-five million, ninety-seven thousand, four hundred eleven".
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