4331401412501 has 8 divisors (see below), whose sum is σ = 4432208789184. Its totient is φ = 4230597540960.

The previous prime is 4331401412497. The next prime is 4331401412537. The reversal of 4331401412501 is 1052141041334.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 4331401412501 - 2² = 4331401412497 is a prime.

It is a super-2 number, since 2×4331401412501² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4331401412801) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1711856 + ... + 3404886.

It is an arithmetic number, because the mean of its divisors is an integer number (554026098648).

Almost surely, 2^{4331401412501} is an apocalyptic number.

It is an amenable number.

4331401412501 is a deficient number, since it is larger than the sum of its proper divisors (100807376683).

4331401412501 is a wasteful number, since it uses less digits than its factorization.

4331401412501 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1752571.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 4331401412501 its reverse (1052141041334), we get a palindrome (5383542453835).

The spelling of 4331401412501 in words is "four trillion, three hundred thirty-one billion, four hundred one million, four hundred twelve thousand, five hundred one".