4331401412537 has 2 divisors, whose sum is σ = 4331401412538. Its totient is φ = 4331401412536.

The previous prime is 4331401412497. The next prime is 4331401412549. The reversal of 4331401412537 is 7352141041334.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2557379870761 + 1774021541776 = 1599181^2 + 1331924^2 .

It is a cyclic number.

It is not a de Polignac number, because 4331401412537 - 2¹⁸ = 4331401150393 is a prime.

It is a super-2 number, since 2×4331401412537² (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4331401412537.

It is not a weakly prime, because it can be changed into another prime (4331401412567) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2165700706268 + 2165700706269.

It is an arithmetic number, because the mean of its divisors is an integer number (2165700706269).

Almost surely, 2^{4331401412537} is an apocalyptic number.

It is an amenable number.

4331401412537 is a deficient number, since it is larger than the sum of its proper divisors (1).

4331401412537 is an equidigital number, since it uses as much as digits as its factorization.

4331401412537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120960, while the sum is 38.

The spelling of 4331401412537 in words is "four trillion, three hundred thirty-one billion, four hundred one million, four hundred twelve thousand, five hundred thirty-seven".