Base | Representation |
---|---|
bin | 1100100110110010011… |
… | …01111000000100100011 |
3 | 1112102000100020202220112 |
4 | 12103121031320010203 |
5 | 24044033100214021 |
6 | 530552055201535 |
7 | 43202431643234 |
oct | 6233115700443 |
9 | 1472010222815 |
10 | 433141023011 |
11 | 15776a8a7514 |
12 | 6bb420762ab |
13 | 31aca692828 |
14 | 16d6d84308b |
15 | b401170d5b |
hex | 64d9378123 |
433141023011 has 2 divisors, whose sum is σ = 433141023012. Its totient is φ = 433141023010.
The previous prime is 433141023001. The next prime is 433141023017. The reversal of 433141023011 is 110320141334.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 433141023011 - 210 = 433141021987 is a prime.
It is a super-2 number, since 2×4331410230112 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (433141023017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 216570511505 + 216570511506.
It is an arithmetic number, because the mean of its divisors is an integer number (216570511506).
Almost surely, 2433141023011 is an apocalyptic number.
433141023011 is a deficient number, since it is larger than the sum of its proper divisors (1).
433141023011 is an equidigital number, since it uses as much as digits as its factorization.
433141023011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 433141023011 its reverse (110320141334), we get a palindrome (543461164345).
The spelling of 433141023011 in words is "four hundred thirty-three billion, one hundred forty-one million, twenty-three thousand, eleven".
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