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43314104013 = 371823247087
BaseRepresentation
bin101000010101101110…
…001100011011001101
311010210122010110112120
4220111232030123031
51202201402312023
631522003323153
73062235544425
oct502556143315
9133718113476
1043314104013
1117407756484
1284899804b9
13411386245b
14214c7b9485
1511d79238e3
hexa15b8c6cd

43314104013 has 16 divisors (see below), whose sum is σ = 58636947456. Its totient is φ = 28434656880.

The previous prime is 43314103961. The next prime is 43314104023. The reversal of 43314104013 is 31040141334.

43314104013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 43314104013 - 28 = 43314103757 is a prime.

It is a super-2 number, since 2×433141040132 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43314104023) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 51756 + ... + 298842.

It is an arithmetic number, because the mean of its divisors is an integer number (3664809216).

Almost surely, 243314104013 is an apocalyptic number.

It is an amenable number.

43314104013 is a deficient number, since it is larger than the sum of its proper divisors (15322843443).

43314104013 is a wasteful number, since it uses less digits than its factorization.

43314104013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 247984.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 43314104013 its reverse (31040141334), we get a palindrome (74354245347).

The spelling of 43314104013 in words is "forty-three billion, three hundred fourteen million, one hundred four thousand, thirteen".

Divisors: 1 3 71 213 823 2469 58433 175299 247087 741261 17543177 52629531 203352601 610057803 14438034671 43314104013